(n^2-4n+5n-20)(n+2)=0

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Solution for (n^2-4n+5n-20)(n+2)=0 equation: 


Simplifying
(n2 + -4n + 5n + -20)(n + 2) = 0

Reorder the terms:
(-20 + -4n + 5n + n2)(n + 2) = 0

Combine like terms: -4n + 5n = 1n
(-20 + 1n + n2)(n + 2) = 0

Reorder the terms:
(-20 + 1n + n2)(2 + n) = 0

Multiply (-20 + 1n + n2) * (2 + n)
(-20(2 + n) + 1n * (2 + n) + n2(2 + n)) = 0
((2 * -20 + n * -20) + 1n * (2 + n) + n2(2 + n)) = 0
((-40 + -20n) + 1n * (2 + n) + n2(2 + n)) = 0
(-40 + -20n + (2 * 1n + n * 1n) + n2(2 + n)) = 0
(-40 + -20n + (2n + 1n2) + n2(2 + n)) = 0
(-40 + -20n + 2n + 1n2 + (2 * n2 + n * n2)) = 0
(-40 + -20n + 2n + 1n2 + (2n2 + n3)) = 0

Combine like terms: -20n + 2n = -18n
(-40 + -18n + 1n2 + 2n2 + n3) = 0

Combine like terms: 1n2 + 2n2 = 3n2
(-40 + -18n + 3n2 + n3) = 0

Solving
-40 + -18n + 3n2 + n3 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.

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